A) Ð’ + 2HN03 -> BN + 02 + H20
B) Ð’ + 6HN03 -+ B2H6 + 6NO + 602
C) Ð’ + 3HN03 -+ HB02 + 3NO + H20
D) Ð’ + 3HN03 -> H3B03 + N02
Ð’ + 2HN03 -> BN + 02 + H20 B) Ð’ + 6HN03 -+ B2H6 + 6NO + 602 C) Ð’ + 3HN
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